tracehook: exec double-reporting fix

The patch 6341c393

 "tracehook: exec" introduced a small regression in
2.6.27 regarding binfmt_misc exec event reporting.  Since the reporting
is now done in the common search_binary_handler() function, an exec
of a misc binary will result in two (or possibly multiple) exec events
being reported, instead of just a single one, because the misc handler
contains a recursive call to search_binary_handler.

To add to the confusion, if PTRACE_O_TRACEEXEC is not active, the multiple
SIGTRAP signals will in fact cause only a single ptrace intercept, as the
signals are not queued.  However, if PTRACE_O_TRACEEXEC is on, the debugger
will actually see multiple ptrace intercepts (PTRACE_EVENT_EXEC).

The test program included below demonstrates the problem.

This change fixes the bug by calling tracehook_report_exec() only in the
outermost search_binary_handler() call (bprm->recursion_depth == 0).

The additional change to restore bprm->recursion_depth after each binfmt
load_binary call is actually superfluous for this bug, since we test the
value saved on entry to search_binary_handler().  But it keeps the use of
of the depth count to its most obvious expected meaning.  Depending on what
binfmt handlers do in certain cases, there could have been false-positive
tests for recursion limits before this change.

    /* Test program using PTRACE_O_TRACEEXEC.
       This forks and exec's the first argument with the rest of the arguments,
       while ptrace'ing.  It expects to see one PTRACE_EVENT_EXEC stop and
       then a successful exit, with no other signals or events in between.

       Test for kernel doing two PTRACE_EVENT_EXEC stops for a binfmt_misc exec:

       $ gcc -g traceexec.c -o traceexec
       $ sudo sh -c 'echo :test:M::foobar::/bin/cat: > /proc/sys/fs/binfmt_misc/register'
       $ echo 'foobar test' > ./foobar
       $ chmod +x ./foobar
       $ ./traceexec ./foobar; echo $?
       ==> good <==
       foobar test
       0
       $
       ==> bad <==
       foobar test
       unexpected status 0x4057f != 0
       3
       $

    */

    #include <stdio.h>
    #include <sys/types.h>
    #include <sys/wait.h>
    #include <sys/ptrace.h>
    #include <unistd.h>
    #include <signal.h>
    #include <stdlib.h>

    static void
    wait_for (pid_t child, int expect)
    {
      int status;
      pid_t p = wait (&status);
      if (p != child)
	{
	  perror ("wait");
	  exit (2);
	}
      if (status != expect)
	{
	  fprintf (stderr, "unexpected status %#x != %#x\n", status, expect);
	  exit (3);
	}
    }

    int
    main (int argc, char **argv)
    {
      pid_t child = fork ();

      if (child < 0)
	{
	  perror ("fork");
	  return 127;
	}
      else if (child == 0)
	{
	  ptrace (PTRACE_TRACEME);
	  raise (SIGUSR1);
	  execv (argv[1], &argv[1]);
	  perror ("execve");
	  _exit (127);
	}

      wait_for (child, W_STOPCODE (SIGUSR1));

      if (ptrace (PTRACE_SETOPTIONS, child,
		  0L, (void *) (long) PTRACE_O_TRACEEXEC) != 0)
	{
	  perror ("PTRACE_SETOPTIONS");
	  return 4;
	}

      if (ptrace (PTRACE_CONT, child, 0L, 0L) != 0)
	{
	  perror ("PTRACE_CONT");
	  return 5;
	}

      wait_for (child, W_STOPCODE (SIGTRAP | (PTRACE_EVENT_EXEC << 8)));

      if (ptrace (PTRACE_CONT, child, 0L, 0L) != 0)
	{
	  perror ("PTRACE_CONT");
	  return 6;
	}

      wait_for (child, W_EXITCODE (0, 0));

      return 0;
    }

Reported-by: Arnd Bergmann <arnd@arndb.de>
CC: Ulrich Weigand <ulrich.weigand@de.ibm.com>
Signed-off-by: Roland McGrath <roland@redhat.com>