x86: fix readb() et al compile error with gcc-3.2.3
Building 2.6.27-rc1 on x86 with gcc-3.2.3 fails with: In file included from include/asm/dma.h:12, from include/linux/bootmem.h:8, from init/main.c:26: include/asm/io.h: In function `readb': include/asm/io.h:32: syntax error before string constant include/asm/io.h: In function `readw': include/asm/io.h:33: syntax error before string constant include/asm/io.h: In function `readl': include/asm/io.h:34: syntax error before string constant include/asm/io.h: In function `__readb': include/asm/io.h:36: syntax error before string constant include/asm/io.h: In function `__readw': include/asm/io.h:37: syntax error before string constant include/asm/io.h: In function `__readl': include/asm/io.h:38: syntax error before string constant make[1]: *** [init/main.o] Error 1 make: *** [init] Error 2 Starting with 2.6.27-rc1 readb() et al are generated by a build_mmio_read() macro, which generates asm() statements with output register constraints like "=" "q", i.e. as two adjacent string literals. This doesn't work with gcc-3.2.3. Fixed by moving the "=" part into the callers' reg parameter (as suggested by Ingo). Build and boot-tested with gcc-3.2.3 on 32 and 64-bit x86. Fixes <http://bugzilla.kernel.org/show_bug.cgi?id=11205>. Signed-off-by: Mikael Pettersson <mikpe@it.uu.se> Signed-off-by: Ingo Molnar <mingo@elte.hu>
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